8y^2-10y+2=0

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Solution for 8y^2-10y+2=0 equation: 



8y^2-10y+2=0

a = 8; b = -10; c = +2;
Δ = b2-4ac
Δ = -102-4·8·2
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-6}{2*8}=\frac{4}{16}
=1/4
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+6}{2*8}=\frac{16}{16}
=1
$

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